Question on: WAEC Mathematics - 2012
The diagram is a circle with centre P. PRST are points on the circle. Find the value of < PRS
A
144o
B
72o
C
40o
D
36o
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Correct Option: A
Reflex < POS = 2x (angle at centre is twice that at circumference)
reflex < POS + < POS = 350o(angles at a point)
i.e. 2x + 8x = 360o
10x = 360o
x = \(\frac{360}{10}\)
= 36o
< PRS = \(\frac{1}{2}\)
< POS(< at centre twice that circumference)
= \(\frac{1}{2}\) x 8x = 4x
4 x 36o
< PRS = 144
reflex < POS + < POS = 350o(angles at a point)
i.e. 2x + 8x = 360o
10x = 360o
x = \(\frac{360}{10}\)
= 36o
< PRS = \(\frac{1}{2}\)
< POS(< at centre twice that circumference)
= \(\frac{1}{2}\) x 8x = 4x
4 x 36o
< PRS = 144
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